load array with set -A problem 1

[nawlej]

Im trying to load an array with set -A but it is space delimited, and I am using strings witn spaces. Does anyone know how to keep the string intact for the array using set -A?

 

[PHV]

And what about proper quoting ?
Can you please post the code and the strings values and the expected result ?

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[nawlej]

welp, if I do something like this:

#!/usr/bin/ksh

set -A services "'string 1' 'string 2' 'string 3'" 


for i in $services
 do
   echo $i
 done

It outputs this:

'string
1'
'string
2'
'string
3'

It still wants to separate by spaces, no matter how I quote the entries. Ideas?

 

[PHV]

With my ksh:
set -A services "'string 1' 'string 2' 'string 3'"
will populate the array with ONE element
set -A services 'string 1' 'string 2' 'string 3'
will populate the array with THREE elements

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[nawlej]

when I populate it like this:

set -A 'string 1' 'string 2'

it only recognizes the first two words (inside the quotes) and runing the nprogram displays this:

String
1

 

[PHV]

For i in $services
I don't think it's the right way to browe an array.
Try something like this:
set -A services 'string 1' 'string 2' 'string 3'
i=0
while [ $i -lt ${#services[*]} ]; do
echo ${services[$i]}; ((i+=1))
done

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[vgersh99]

#!/bin/ksh

s1='string 1'
s2='string 2'

IFS='
'
set -A services ${s1} ${s2}

typeset -i i=0
while (( i < ${#services[*]} ))
do
   print "i->[${i}] services->[${services[$i]}]"
   (( i=i+1 ))
done

vlad
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