Little problem with Arrays

[Frihi]

Dings1=[];
Dings3=[1,2,3];
Dings4=[3,4,5];
Dings1=Dings3.concat(Dings4);
returns: 1,2,3,3,4,5.

But I want just 1,2,3,4,5. Of course at runtime I don't know if there are any double values but it might be so.

I suppose somebody can help me. Thanks.

 

[frozenpeas]

Try this:

Dings1 = [];
Dings3 = [1, 2, 3];
lastDings3 = Dings3.length-1;
Dings4 = [3, 4, 5];
if ((Dings3[lastDings3]) == (Dings4[0])) {
	tmp = Dings3;
	tmp.pop();
	Dings1 = tmp.concat(Dings4);
} else {
	Dings1 = Dings3.concat(Dings4);
}[code]

 

[Frihi]

I may not have explained it clearly. The elements of the arrays can change, so sometimes there are repeated values, sometimes not. Your code only takes the last elemant of that array to compare, but I need to compare all values. Any values.
Thanks anyway.

 

[BigBadDave]

This is a duplicate checking function I made:

function checkDup (arr) {
	var chk = new Array();
	var dup = false;
	for (var i = 0; i<arr.length; i++) {
		for (var x = 0; x<chk.length; x++) {
			if (chk[x] == arr[i]) {
				dup = true;
			}
		}
		if (!dup) {
			chk[chk.length] = arr[i];
		}
		dup = false;
	}
	return chk;
}
var foo;
var foo1 = new Array(1, 2, 3);
var foo2 = new Array(3, 4, 5);
foo = foo1.concat(foo2);
foo = checkDup(foo);
foo.sort();
for (var i = 0; i<foo.length; i++) {
	trace (foo[i]);
}

Regards
David Byng

http://www.byngdesigns.co.uk

davidbyng@hotmail.com