Listing 6 digit numbers not 3 1

[maxcrook]

I have a file that contains data like so

012345
012346
012345
123
012567
109
107

but i want to list only the numbers that are 6 characters in length - any ideas how to remove the ones with 3 characters ?

 

[aigles]

The following sed command removes numbers whith 3 digits (and keep all others).
[tt]sed '/^[0-9]\{3\}$/d' input_file[/tt]

This second command keeps only numbers with 6 digits
[tt]sed -n '/^[0-9]\{6\}$/p' input_file[/tt]


Jean Pierre.

 

[maxcrook]

Great thanks - i had a horrible feeling it would be a sed command ! Thanks again.

 

[PHV]

If you prefer awk:
awk 'length==6' /path/to/file

Hope This Help, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884

 

[Ygor]

Or: [tt] grep ...... file[/tt]