Listarray question

[ilovelinux2006]

Hello everyone,

If I have the method:
<Li
public Cars findByNumber(String carNumber){
private ListArray<Object> car = new ListArray<Object>();

Now If I convert the String into an Integer:
Integer carnum = new Integer(carNumber);
-- and someone passes letters instead of numbers in the string, I cannot upcast:

Cars whatcar = (Cars)car.get(carnum);

That will come out with an error if the string is anything other than numbers (integers). Is there another way to get a list arrays object other than with an int value, instead a string?

 

[Diancecht]

What is a ListArray?

You cannot build an Integer with letter, anyway.

Cheers,
Dian

 

[jstreich]

First, if this is homework, don't post here. See the terms and conditions of the site.

Second, please use code tags to post code.

Third, what is a Listarray defined as?

Fourth,

public Cars findByNumber(String carNumber){
 private ListArray<[red]Object[/red]> car = new ListArray<[red]Object[/red]>();

Why Object and not Cars?
If objects, why not use an ArrayList()

Fifth,

Integer carnum = new Integer(carNumber);
Cars whatcar = (Cars)car.get(carnum);

Er, get in List and ArrayList take int not Integer. Consider:

[red]try{
  int[/red] carnum = Integer[red].parseInt[/red](carNumber);
  Cars whatcar = (Cars)car.get(carnum);
[red]}catch(NumberFormatException e){
  //do error stuff here
}[/red]

Changes in red.

Integer.parseInt(...) is a static method that returns the numaric value of a string representation of a number, and throws a NumberFormatException if the passed string isn't an integer (read: has letters, punctuation or is a float).

If this homework, and it seems to contrived not to be, please talk to your instructor and get help.

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