list::iterator & const 2

[AMosmann]

if I want to declare a copy-constructor or a operator= like

X::X(const X &x);
X &X:perator={const X &x};

x has a member std::list<AnyType>;

if I do the following:
X::X(const X &x){
std::list<AnyType>::iterator it=x.anylist.begin();
...
};

the compiler tells me:

error C2679:
binary operator '=' : No operator '=', that accepts a righthand operator
'class std::list<class AnyType,class std::allocator<class AnyType> >::const_iterator'

[COLOR=$991111]Binaerer Operator '=' : Kein Operator definiert, der einen rechtsseitigen Operator vom Typ 'class std::list<class AnyType,class std::allocator<class AnyType> >::const_iterator' akzeptiert (oder keine geeignete Konvertierung moeglich)[/color]

how can I step through a const list ?
the way I found was to copy the list and step throuug this one, but there must be other ways, isn't?



Greetings Andreas

 

[Cagliostro]

You can try this, maybe it would help, maybe not.
std::list<AnyType>::iterator it = (std::list<AnyType>::iterator)x.anylist.begin();


Ion Filipski

ICQ: 95034075
AIM: IonFilipski
filipski@excite.com

 

[JOLESEN]

Not sure if I understand your problem fully, but a const_iterator instead of iterator may fix the problem.

/JOlesen

 

[palbano]

X::X(const X &x){
std::list<AnyType>::[red]const_[/red]iterator it=x.anylist.begin();
...
};


-pete

 

[AMosmann]

Thanx, was a great help

)


Greetings Andreas