line continuation

[cat5ive]

Hi,

puts("enter last name, first name, id# separated");//line1
puts("by spaces, then press enter."); //line2

Can I combine these 2 puts() into 1. For example

puts("enter last name, first name, id# separated //line1
by spaces, then press enter."); // line2

I know my example doesn't work, but just to give you an idea of what I want.

Thanks in advance.

 

[jstreich]

Yes, and that should compile (w/o the comment in the middle)

puts("enter last name, first name, id# separated  
    by spaces, then press enter.");

But you probably want to use escape chars:

\n  newline  to get a new line
\t  tab      to get a tab
\0  null     to get a null char
\\  \        to get a \, sine \ is the escape char

So you'd want to do:

puts("enter last name, first name, id# separated[green]\n[/green]by spaces, then press enter.");

Note that it is right against the other text, this is so that you don't get a space at the begining of the second line You can seperate it from the word seperated, but not from the word by w/o changing the format.

 

[cat5ive]

some how I need the this '\' at the end of the line. It works like this.

puts("enter last name, first name, id#\
separated\nby spaces, then press enter.");

Thanks jstreich

 

[DaveSinkula]

   puts("enter last name, first name, id# separated "  // line1
        "by spaces, then press enter.");               // line2

 

[jstreich]

Enter chars shouldn't be in string literals, even if allowed... You should use \n ... Using returns in a string literal should create a compiler warning if the compiler is worth it's salt.

 

[cat5ive]

Hi jstreich,

Enter char? Do you mean \? In my original code
puts("enter last name, first name, id# separated
by spaces, then press enter.");,
the compiler was asking for the '\' (which I didn't notice in the first place).

Another question, can I declare and initialize pointer in the same statement? Instead of coding them separatly like the below.
int *ptr;
ptr = &var;

Thanks again

 

[cat5ive]

Never mind, got it.

 

[jstreich]

I said \n
for newline. the \ is an escape
\' and \" are how to get a the chars ' and " (respectivly). Without them the compiler will thing you are want to end or begin a literal.