Least cost routing setup

[rinop]

Hi,

we have a MD110 BC11 SP12 and now i have to plan LCR(least cost routing) of another carrier.
I have read various posts on this matter and now before beginning to make damages, I ask to you a confirmation on how much I have understood.
now in the system there is not set any lcr never the rates were good but one day a carrier has made us a good proposal to save money.
You look to the following data:

<NADAP:NUMTYP=LC;
GIVES NUMBER ANALYSIS
TYPE OF SERIES NUMBER SERIES

END


<Lcddp:tab=dnt1;
NOT ACCEPTED
ENTRY NOT FOUND

<Lcddp:tab=dnt2;
NOT ACCEPTED
ENTRY NOT FOUND

<Lcddp:tab=ENT;
NOT ACCEPTED
ENTRY NOT FOUND

<Lcddp:tab=FDT;
NOT ACCEPTED
FRCT-VALUE
NOT ASSIGNED

<RODDPEST=ALL;
GIVES EXTERNAL DESTINATION ROUTE
DEST DRN ROU CHO CUST ADC TRC SRT NUMACK PRE
0 2 002500000000025001000000 0 2 0
20 1 002500000000025001000000 0 2 0
25 2 002500000000025000000000 0 2 0
24 3 002500000000025000000000 0 2 0


IF I HAVE UNDERSTOOD AS BEFORE WELL THING I HAVE TO PLAN THE CODE OF LCR CON

NANSI:NUMTYP=LC,NUMSE=9; FOR EXAMPLE

then i have to create the table dnt2

LCDDI:TAB=DNT2,ENTRY=00047,TRC=1,ACCT=0,FRCT=1,TOLL=111111111111111,BTON=0;

then i create the virtual table FDT

LCDDI:TAB=FDT,FRCT=1,TZONE=1,PRE=555;

finally to insrt the bundle

RODDIEST=555,ROU=1, TRC=4,SRT=5,PRE=55500047;
RODDIEST=555,ROU=20,CHO=1,TRC=4,SRT=5,PRE=55500047;
RODDIEST=555,ROU=25,CHO=2,TRC=4,SRT=5,PRE=55500047;
RODDIEST=555,ROU=24,CHO=3,TRC=4,SRT=5,PRE=55500047;
It's correct ?

It's a right sequence?

Tks a lot

p.s. Excuse for my english

 

[whosrdaddy]

roddi is a bit confusing for me.

what do you want send onto your route?

I suppose you want to send 0047xxxx to the network when a user composes 00047xxxx.

if this is the case this is the only correct way :

this means you need to put 0 into LC (otherwhise no LC check)

NANSE:NUMSE=0,NUMTYP=ED;

NANSI:NUMSE=0,NUMTYP=LC;

Leave dest 0 in your roddi, in case of problems, just put 0 into ED and everything is back to normal

put 00047 into DNT1
exception calls are caught in DNT2
LCDDI:TAB=DNT1,ENTRY=00047,TRC=1,FRCT=1; // catch 00047 calls, leading 0 is truncated here
LCDDI:TAB=DNT1,ENTRY=0,TRC=1,FRCT=2; // catch all other 0x calls here

LCDDI:TAB=FDT,FRCT=1,TZONE=1,PRE=555;
LCDDI:TAB=FDT,FRCT=2,TZONE=1,PRE=556;

NANSI:NUMSE=555&556,NUMTYP=ED;

RODDIEST=555,ROU=1,SRT=4,ADC=; //put correct ADC parameter depending on the route
RODDIEST=555,ROU=20,SRT=4,CHO=1,ADC=;
RODDIEST=555,ROU=25,SRT=4,CHO=2,ADC=;
RODDIEST=555,ROU=24,SRT=4,CHO=3;

RODDIEST=556,.... //program the same as dest 0

That should be about it, hope that helps /clarifies.

Cheers,
Daddy

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[mundus]

This shall be in DNT2:

LCDDI:TAB=DNT2,ENTRY=0,TRC=1,FRCT=2; // catch all other 0x calls here

 

[rinop]

HI Whosrdaddy,
HI mundus,

that's you wrote it's right and i confirm that in my external number plane "0" is already set and what I have now learned is that it needs to also insert "0" in the LC otherwhise that don't work properly. I want to thank you for your confirmations to my suppositions. Next week I will make the tests of operation and if something doesn't go I will still ask suggestions to you.

Many thanks for your technical support.

 

[whosrdaddy]

mundus, you're correct (those damn typos )

good luck rinop!

-----------------------------------------------------
What You See Is What You Get
Never underestimate tha powah of tha google!

 

[rinop]

Hi,

I have planned lcr and it works well !