Leading zeros

[SMerrill]

How do I print an integer with leading zeros, i.e. the value 6 printed as 0006 and the value 15 printed as 0015?

 

[dnivraramuk]

U can try this:

VAR_1 =sprintf("%.4d",value);

The VAR_1 will contain the desired result.

 

[marsd]

Thanks for the workout
I was getting rusty.

I did it from an input like this:
hjdjnmjd67md8dk349dmcd89f943m39d93m2
8rmdfnmf6e84mdrhf7ri4ner7f894m3nfr78
784jemd7e3i238fnmjie78rnmf7fr83mrmg7

The script looks like this:
function Zeros(str, list) {
while (match(str,/[0-9]+/) != 0) {
list = length(list) < 1 ? substr(str,RSTART,RLENGTH) : list substr(str,RSTART,RLENGTH)
printf &quot;Old string = %s , LIST = %s\n&quot;, str, list
str = substr(str,RSTART + RLENGTH,length(str) - RSTART + RLENGTH)
printf &quot;New string = %s\n&quot;, str
}
list = addZeros(list)
return list
}

function addZeros(str, i,zlist,len) {
i=0
len = length(str)
while (i++ <= len) {
zlist = length(zlist) < 1 ? str : &quot;0&quot; zlist
}
return zlist
}


{
mylist = Zeros($0)
print mylist
}

Try it, it's a lot of fun.
Hopefully this gives you an idea if you need it
for parsing data containing numbers, etc..

Your initial problem can be handled easily:
function addZeroto(str) {
if (length(str) == 1) {
return &quot;000&quot; str
} else if (length(str) == 2) {
return &quot;00&quot; str
} else if (length(str) == 3) {
return &quot;0&quot; str
} else {
return str
}
}

 

[SMerrill]

Thanks, folks. I ended up using this:

printf(&quot; %03d &quot;,i)