lat/long to bearing

[elck]

Hi all,

Suppose I have two coordinates like

Lat 28,00123 E Long 33,00001 S
and
Lat 28,00123 E 34,76501 S

How could I calculate the bearing in degrees of that track?

The math is simply to hard for me!

 

[sleipnir214]

Are you asking a PHP question or a math question?



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[elck]

PHP

I have an EXCEL answer, but that makes no sense to me.
It read likes this, anyone feel like translating this??

=ROUND(IF(D8=F8;IF(C8>E8;0;180);IF(SIN(D8*PI()/180-F8*PI()/180)<0;ACOS((SIN(-E8*PI()/180)-SIN(-C8*PI()/180)*COS(ACOS(SIN(-C8*PI()/180)*SIN(-E8*PI()/180)+COS(-C8*PI()/180)*COS(-E8*PI()/180)*COS(-D8*PI()/180+F8*PI()/180))))/(SIN(ACOS(SIN(-C8*PI()/180)*SIN(-E8*PI()/180)+COS(-C8*PI()/180)*COS(-E8*PI()/180)*COS(-D8*PI()/180+F8*PI()/180)))*COS(-C8*PI()/180)))*180/PI();(2*PI()-ACOS((SIN(-E8*PI()/180)-SIN(-C8*PI()/180)*COS(ACOS(SIN(-C8*PI()/180)*SIN(-E8*PI()/180)+COS(-C8*PI()/180)*COS(-E8*PI()/180)*COS(-D8*PI()/180+F8*PI()/180))))/(SIN(ACOS(SIN(-C8*PI()/180)*SIN(-E8*PI()/180)+COS(-C8*PI()/180)*COS(-E8*PI()/180)*COS(-D8*PI()/180+F8*PI()/180)))*COS(-C8*PI()/180))))*180/PI()));0)

But rather I hope someone has an answer that is a little simpeler!

 

[sleipnir214]

It would proably be easier to start here:

http://mathforum.org/library/drmath/view/55417.html

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[elck]

Looks good, Sleipnir, I'll dig into that.
Thanks