Nov 28, 2006 #1 stephm923 Programmer Nov 28, 2006 9 US I need to create a formula that will give me the last day of the current month (ex. 2006-11-30)
Nov 28, 2006 #2 synapsevampire Programmer Mar 23, 2002 20,180 US Try: dateserial(year(currentdate),month(currentdate)+1,1)-1 -k Upvote 0 Downvote
Nov 28, 2006 #3 bdreed35 Programmer Mar 2, 2003 1,549 US Here is one way to do it: dateadd("m",1,minimum(monthtodate))-1 ~Brian Upvote 0 Downvote
Nov 28, 2006 #4 lbass Technical User Feb 9, 2002 32,816 US Try: dateserial(year(currentdate),month(currentdate)+1,1)-1 -LB Upvote 0 Downvote
Nov 28, 2006 Thread starter #5 stephm923 Programmer Nov 28, 2006 9 US Worked like a charm. Thanks!! Upvote 0 Downvote