last day of a month 1

[w5000]

hello,
with the date command on a linux I can obtain last day of the current month:

$ date +%e -d "-$(date +%d) day"
30

How to modify the command to get with the command any month's last day?

I tried this but it return wrong value...

$ date +%e -d "02/02/2016 -$(date +%d -d "02/02/2016") day"
31

 

[w5000]

I get some results with this:

$ date +%e -d "+1 month -$(date +%d) days"
31
$ date +%e -d "02/02/2016 +1 month -$(date +%d -d"02/02/2016") days"
29
$ date +%e -d "02/02/2015 +1 month -$(date +%d -d"02/02/2015") days"
28
$ date +%e -d "02/02/2014 +1 month -$(date +%d -d"02/02/2014") days"
28
$ date +%e -d "02/02/2013 +1 month -$(date +%d -d"02/02/2013") days"
28
$ date +%e -d "02/02/2012 +1 month -$(date +%d -d"02/02/2012") days"
29
$ date +%e -d "07/02/2012 +1 month -$(date +%d -d"07/02/2012") days"
31
$ date +%e -d "08/02/2012 +1 month -$(date +%d -d"08/02/2012") days"
31
$ date +%e -d "09/02/2012 +1 month -$(date +%d -d"09/02/2012") days"
30
$ date +%e -d "06/02/2012 +1 month -$(date +%d -d"06/02/2012") days"
30
$

 

[feherke]

Hi

Kind of cheating, but may I suggest an alternative ?

[blue]master #[/blue] cal | awk 'NF{l=$NF}END{print l}'
31

[blue]master #[/blue] cal 2 2015 | awk 'NF{l=$NF}END{print l}'
28

Regarding your [tt]date[/tt]-based solution, I would also calculate that way.


Feherke.
feherke.ga