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join all tasks

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phpatrick

Programmer
Jul 9, 2006
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BE
Code:
YEAR	MNR    ID TASK  MAAND	TOTUURSHIFT1
2006	08	4 WORT	august	49,13
2006	08	3 POMP	august	8,68
2006	08	7 ONDE	august	3,77
2006	08	6 GRAS	august	3,82
2006	08	8 DIVE	august	171,55
2006	08	2 COUR	august	118,25
2006	08	1 AARD	august	124,55
2006	08		august	0,00

I have this question : there are for the moment 8 task (in the future it could be less or more). During one month you worked on some tasks. But sometimes not. Above there is one task where I did not work on. I know this but with this query I don't know for which task. I should know becuase I will related this with other tables to get a total for a task in a month.

Code:
SELECT Format([DAG],"yyyy") AS [YEAR], Format([DAG],"mm") AS MNR, T_00_TEELT.ID_TEELT, T_00_TEELT.TEELT_TAKEN, Format([DAG],"mmmm") AS MAAND, Sum(DateDiff("n",[SHIFT1VAN],[SHIFT1TOT])/60) AS TOTUURSHIFT1
FROM T_00_TEELT RIGHT JOIN T_03_TIME ON T_00_TEELT.ID_TEELT = T_03_TIME.refTEELTSHIFT1
WHERE (((T_03_TIME.DAG) Between DateSerial(Year(Date())-1,2,28) And DateSerial(Year(Date()),4,1)))
GROUP BY Format([DAG],"yyyy"), Format([DAG],"mm"), T_00_TEELT.ID_TEELT, T_00_TEELT.TEELT_TAKEN, Format([DAG],"mmmm")

Is this a join question. With this join he should take ALL the records of the TASKS (TEELT) even when there is none hour prestated for it.
 
In the SELECT list and the GROUP BY clause replace T_00_TEELT.ID_TEELT with T_03_TIME.refTEELTSHIFT1

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886
 
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