is there a way to pass a variable i

[PuPPeT2]

is there a way to pass a variable into an awk statement from out site the statement?

variable="hello world"
cat file| awk '
{
print "variable from outside awk:"variable
}'

where would we all be w/out awk, sed and grep?

 

[PuPPeT2]

i guess i could have asked if there was a way to reference variables from outside an awk statement in an awk statement too or perhaps instead

 

[CaKiwi]

Like this

cat file| awk -v var=$variable '
{
print "variable from outside awk:" var
}'


CaKiwi

"I love mankind, it's people I can't stand" - Linus Van Pelt

 

[PuPPeT2]

very cool - thank you

 

[grega]

There's a few ways. Read my FAQ ... Faq271-1281

Greg.

 

[vgersh99]

UUOC - sorry for nit-pickin'

awk -v var=$variable '{print "variable from outside awk:" var }' file

vlad
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