insert blank line after each \f\r

[dbase77]

Hi,

I have a file which contains \f\r. How do I go about inserting blank line after each occurrence of \f\r?

I used this to replace \r with \f\r. Now I want to insert blank line after it.

nawk 'NR%94==0{sub(/\r/,"\f\r")}1' $x > /tmp/$filename.temp

Thanks.

 

[PHV]

nawk 'NR%94==0{sub(/\r/,"\f\r[!]\n[/!]")}1' $x > /tmp/$filename.temp

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[dbase77]

Thanks PHV. How could I forgot about \n.

I've used this to insert blank line but only if the line is blank. If the line is not blank, it won't insert it. Anyway I can change it to insert blank line whether it contain text or not. Thanks again.

awk '{print}NR%98==0{print ""}' /tmp/$filename.temp2 > $x