including a variable inside awk script 2

[fejjalh]

In fact, I want to print the second column of different files where the first column contains the name of these files.
The command is
awk '$1==file1' {print $2++} file1
Well Iwant to do this for many files by replacing file1 with a variable item $filename.
Thank you.

 

[aigles]

See FAQ faq271-1281

Jean Pierre.

 

[futurelet]

This should do it:

$1==FILENAME{print $2}

Let me know whether or not this helps.