include_once points to an other directory

[solo1234]

Hello PHP users,

In my script I am using the next script:

include_once('a.php');

The functions in a.php can't be called because 'a.php' is located in an other directory.

I tried:
include_once('../pages/a.php');
include_once('..//pages//a.php');
include_once('..\pages\a.php');
include_once('..\\pages\\a.php');
include_once('./pages/a.php');

But is was not possible to call the functions.
Can someone please give me the right syntax to call the php file from an other directory?

Nice regards,
Michelle.

 

[jpadie]

the answer to your question depends on where the other directory is located. can you elucidate?

 

[solo1234]

Hello jpadie,

Thanks for the reaction

Structure of the page:

http://w.com/pages/a.php

http://w.com/forum/b.php

Information of b.php
include_once('../a.php');
<function call to what is placed into a.php>

The functions from a.php can't be reached

When b.php is placed in the pages directory with:
include_once('a.php');
There is no problem.

Hopefully you can help me.
Michelle.

 

[Vragabond]

Since double dot (..) means parent directory, your script is in effect saying the following:

include_once ('[URL unfurl="true"]http://w.com/a.php');[/URL]

From your example it is obvious that a.php is not in the webroot but in another subdirectory called pages. So, changing it really reference the pages directory would be:

include_once('../pages/a.php');

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[jpadie]

i suspect you want

include_once '../[red]pages[/red]/a.php';

the '..' traverses the directory structure up one directory. since your files are in different sub directories you then need to traverse the structure down to the right directory before addressing the basename.

note that as include and require (and their _once variants) are language contructs rather than functions, the brackets are not required and are ignored if included (making them optional).

 

[solo1234]

Thanks for the information.

Michelle.