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include ('$joshrant');
- Thread starter kpdvx
- Start date
danielhozac
Programmer
I think that ' makes PHP treat all text inside as it is, it doesn't translate variables into values. Try and remove the ''. //Daniel
Correct. You can use full ("$variable"
quotes if you want, but that is only useful if you have other text along with your variable. But PHP uses the single quotes to treat everything inside as plain text, inlcuding variable names.
Also, do not confuse single quotes with the backtick (``), which does command-line execution of everything inside it. ($myvar = 'ls -la'; would make your variable string equal to the list of files in the current Unix directory). -------------------
Current reading --
quotes if you want, but that is only useful if you have other text along with your variable. But PHP uses the single quotes to treat everything inside as plain text, inlcuding variable names.Also, do not confuse single quotes with the backtick (``), which does command-line execution of everything inside it. ($myvar = 'ls -la'; would make your variable string equal to the list of files in the current Unix directory). -------------------
Current reading --
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