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in a loop... 1

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ogniemi

Technical User
Nov 7, 2003
1,041
PL

I need to get (in easy way) in "for" loop output:

aa
ab
ac
..
..
..
zy
zz

thx in advance,!
 
A starting point:
awk 'BEGIN{for(i=97;i<=122;++i)for(j=97;j<=122;++j)printf "%c%c\n",i,j}'

Hope This Helps, PH.
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