Image Probs!

[7724]

Hi Guys,

I’m trying to display an image on a live php page, wihich is already uploaded to a directory:

So in my admin section I have this code:

<select name="image">
<option value="" selected>select an image...</option>
<?php
$query = mysql_query("SELECT * FROM `images`");
while($reza = mysql_fetch_assoc($query)){
?>
<option value="<?php echo $reza['url']; ?>"><?php echo $reza['name']; ?></option>
<?php
}
?>
</select>

Now this is a dropdown list which looks in my SQL images table for each image in the directory. This tale holds the name of the image, which is displayed on the dropdown.

What I want to do is make a form (post) the above so that when submit, the selection I have made is held in memory and I can go in and change that image as needed – then the selected image is displayed on my live site using;

<img src="images/<?php echo"$image"; ?>">

Not sure how I’d modify the dropdown though to do this, so it can be modified and the selection is held.

Any ideas?

Thanks

 

[jpadie]

not certain that i fully understand your question.
but .. it seems like what you want to do is not display the image directly but to do some manips first.

not a problem.

from the form you have the name of the image.
use php to execute the image manipulations on the image and save it as a new image (or whatever) and then populate the src attribute of the img tag with the new file name (or whatever).

 

[7724]

Hi,

Bit further on using this code:

Yep that's the idea! But with this:



php:
--------------------------------------------------------------------------------

<?php
if (isset($_POST['image'])){
$selected = $_POST['image'];
$selected_display = $_POST['image'];
} else (
$selected = "";
$selected_display = "select an image...";
}
echo "
<select name='image'>
<option selected value='$selected'> $selected_display </option>
";
$query = mysql_query("SELECT * FROM `images`");
while($reza = mysql_fetch_assoc($query)){
$name = $reza['name'];
$location = $reza['url'];
echo " <option value='$location'>$name</option>";
}
echo "</select>";
?>


--------------------------------------------------------------------------------



Throws up an error:

Parse error: parse error, unexpected ';' in /home/sleaz/public_html/cms/add_profiles.php on:

= ""; $selected_display = "select an image..."; } echo

Any ideas?

Ta

 

[jpadie]

you have a round bracket after the else statement rather than a curly brace.