if statement inside an echo? 1

[coolicus]

In my edit page of my cms I am writing the form and populating it if there is content existing, but how do I check if the checkbox has a value of 1, if so then echo 'checked'?

Here is what I am doing

$query1=" SELECT * FROM properties where id = '{$_GET['id']}' ";
$result1=mysql_query($query1);
$rs = mysql_fetch_array($result1, MYSQL_ASSOC);

echo "<form method='post' action='editscript.php'>" .
"<input type='hidden' name='id' value='{$rs['id']}'>" .
"<span class='MainText'>Property Name: </span><br /><input type='text' name='name' value='{$rs['name']}' class='admininputs'>" .

"<br /><span class='MainText'>Property Address: </span><br /><input type='text' name='address' value='{$rs['address']}' class='admininputs'>" .

"<br />pool <input type='checkbox' value='1' name='pool' />.

"<br /><input type='submit' value='submit'></form>" ;

So I need to check if pool has a value of 1, then echo checked but can I do this inside an echo?

 

[Foamcow]

Break out of the echo, do your conditional check, echo something else based on the result of the check.


You may find it easier to do a check, set a variable and then write that variable into your echo.

I do it like this

$check = "";
if($data['checkbox']==true){
   $check = " checked=\"checked\" ";
}

echo("<input type="checkbox" {$check} name="blah" />");

You might also find it simpler to break out of PHP alltogether when writing the HTML then just echo the value where needed by using

<input type="checkbox" <?=$check;?> name="blah" />

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[coolicus]

that worked great thanks