If else function - but not based on id 1

[sinbadly]

I need to call an image from homepage (default.php) and from pages within.

Normally, I use if id='something', but this time I need to say if the page is the default page ...

Be grateful to know how I would name the default page rather than an ID, like this -

if($_GET['id'] == '' OR $_GET['id'] == 0)
{
echo '<img src="images/sept/al.gif" title="We want writers and artists!">';
}
elseif($_GET['id'] >= 1 )
{ echo '<img src="../images/sept/al.gif" title="We want writers and artists!">';
}

 

[thedaver]

if (!isset($_GET['id'])) {......}

I believe this allows for a case of an empty GET string, or at least no value for "?id="



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http://www.dermanagement.com/

 

[sinbadly]

Thanks, thedaver, but the homepage doesn't have an id number and nor do many of the pages within, that's the trouble.

Wouldn't I have to code something like

if($_GET['page or something'] == 'default.php or something' )

? Cheers

 

[sinbadly]

What it does, thedaver, is certainly to allow the image to appear on each page, only it duplicates it.

So obviously you have put me on the right track, and many thanks. I'll have a fiddle with it tonight. Cheers

 

[jpadie]

what about

if (basename(__FILE__) === "default.php"){
 //put default image up
}else{
 //put some other image up
}