I want to know address of member functions 1

[JimmyK]

Hi, i have this smal program



int Dummy() {}

Class Cat
{
public:
Cat(){}
int GetAge(){return MyAge;}
private:
int MyAge;
}


int main
{
int (Cat::*p1() = Cat::GetAge;
int (*p2) = Dummy;

cout << p1 << endl;
cout << p2 << endl;


}



&quot;cout << p2&quot; print the adress of Dummy function but &quot;cout << p1:&quot; doesnt.

What i want is : priting the address of GetAge function.

How can i do that?

Thanks a lot

Jimmy


mailto:nhan_tiags@yahoo.com

 

[Cagliostro]

This is one idea about function's address. In this sample, you can know address of function only after calling it. The address of current function is always in the register ebp.
//--------address.cpp-----------
#include<iostream>
using namespace std;
int address;
class Cat
{
public:
Cat(){}
int GetAge()
{
_asm mov [address],ebp;
return MyAge;
}
private:
int MyAge;
};

int main()
{
Cat d;
int (Cat::* a)()=0;
cout<<address<<endl;
d.GetAge();
cout<<hex<<address<<endl;
return 0;
}
//--------address.cpp-----------

 

[JimmyK]

Thanks a lot, JolnFill
But i wonder this is the only way?

Jimmy

mailto:nhan_tiags@yahoo.com

 

[Cagliostro]

Sorry, maybe it exists but I don't know an other way...

 

[JimmyK]

Hi JolnFill,
Your post is very helpfull but you was confused that THIS pointer points to object itself, not to member functions . Here is the code for test



#include <iostream>
using namespace std;

int addr = 0;

class Cat
{
public:
Cat():MyAge(0){}
int GetAge()
{
_asm mov [addr],ECX
return MyAge;
}
private:
int MyAge;

};

int main()
{
int (Cat::*p2)()=Cat::GetAge;

Cat Cat1;
Cat *pCat=&amp;Cat1;
Cat1.GetAge();
cout << hex << addr << endl;
cout << hex << pCat << endl;
return 0;
}




Jimmy

(Helps never hurt....)




mailto:nhan_tiags@yahoo.com

 

[JimmyK]

Hi all,
I have found the way to print Cat::GetAge()
cout << hex << *(void **) &amp;p2 ;

Hope this is a useful tip.

Jimmy
mailto:nhan_tiags@yahoo.com