how to validate the value is digit pls ...

[h3nd]

Hi guys,

I have to tried to validate whether the value is digit. I have tried this one but it's not working.

 [[ "$f" == "[[:digit:]]" ]]

anyone can help me ??
Thx

 

[kHz]

[[ $f == [0-9] ]]

Ever think of buying the O'Reilly "Learning the Korn Shell" book? It would answer most of the questions you ask.

 

[PHV]

A portable way:
case $f in
*[!0-9]*) echo $f BAD;;
*) echo $f OK;;
esac

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[h3nd]

Thx guys,

kHz, the problem is my number could be many digits.

PHV, thx. but I think it's better using :
[[ $f == [0-9][0-9][0-9][0-9][0-9][0-9] ]]

 

[PHV]

It's better if you want a number with exactly 6 digits.