How to return count of eleement in lindex

[snowingnow]

I use following script to reformate a string
..
set fieldo [split $segment |]
set field1 [lindex $fieldo 13]
set field2 [lindex $fieldo 14]

In field2, there may have some sub segments in it,some time only one, if have more than one then split by "^",
My question is how to i determine how many element in the field2, bascially i want to retrieve index of 0(first one) and 7(filed 8) if they have..
How can i do that?
Thanks

 

[feherke]

Hi

How to return count of eleement in lindex

puts "The list has [llength $fieldo] elements"

Or if you only want to know if there are one or more substrings, then check if the string contains the separator character. [tt]string first[/tt] will return -1 if the separator is not found.

string first "|" $segment

At least as I understood the subject. ( No idea what you asked in the question itself. )

Feherke.

http://rootshell.be/~feherke/

 

[snowingnow]

Thank for the quick reponse..
You right i can use string first "^" $segment to determine if there are subsring in it, but i what to know how many substrings in it.. the reason i am asking is: let say if the string only contains 3 sub strings sperated by "^", i want a way to get max index number.. Thanks

 

[feherke]

Hi

Then [tt]split[/tt] it and use [tt]llength[/tt] on the resulted list.

Feherke.

http://rootshell.be/~feherke/

 

[Bong]

The split command can have more than one delimiter characters specified. If you don't care about preserving the original "|" separation prior to the "^" separation, you can split on both at once:

split $segment {| ^}

_________________
Bob Rashkin