how to replace string in vi with "./" character 1

[baggetta]

Can you show me how to replace the following string in vi.

a ./temp/db
a ./temp/db

change it to:
a /db/new
a /db/new1

 

[p5wizard]

:1,$ s/^a ./a /

would do the trick

HTH,

p5wizard

 

[Annihilannic]

Instead of using :s/water/wine/ you can use any character in place of the "/", for example :s#water#wine#.

Alternatively you could escapae the '/' characters in your search and replace strings, i.e. use '\/'.

Annihilannic.

 

[PHV]

:%s!\./!/!

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[baggetta]

thanks for the tips...i found nled editor from AIX and put it on Linux...much easier.