How to read Second field in awk

[beaster]

In my file file# there is text RXOCF, in the field accross from this text, there is a two digit number. Like 60 or 62. I need to grab that number and find the text TG_TEI in the first pre_build_b# file and replace it, but keep using the end number to the output file pre_build_c#

Here is what I have so far that create the new file, but it grabs the whole original file# file, I just need that text next to RXOCF, the example is below:

The file file#:

<RXMOP:MO=RXOCF-11;


RADIO X-CEIVER ADMINISTRATION
MANAGED OBJECT DATA

MO TEI SWVERREPL SWVERACT SIG
RXOCF-11 62 DEFAULT B0531R0702 CONC

BSSWANTED NEGSTATUS
90 SUCCESSFUL

My Script:

/RXOCF/ {
fn = FILENAME
sub(/^[^0-9]*/,&quot;&quot;,fn)
fn1 = &quot;file&quot; fn
fn2 = &quot;pre_build_c&quot; fn
num = $2
while ((getline < fn1 ) > 0) {
gsub(/TG_TEI/,num)
print > fn2
}
close(fn1)
close(fn2)
}

 

[beaster]

Has anyone been able to review this for me??

 

[beaster]

I already worked it out, my resolution was to add the TEI value to the input master_sorted file and just read it in the beginning! It works.