How to print the line matching pattern and a specif line after

[cicalons]

I would like you help in order to achieve this:

I have to print the line matchi pattern and this is OK,but at the same time print
a specific line after: for exmple the third, the fourth etc ..... .

But only the pair of lines above reported:
- the one matching the string
- and jsut the specifi line (3, 4 5 , 6 .....) NOt the other lines between(in teh middle).
Example: I search for "BBBB" string:

AAAA BBBB CCCC DDDD
EEEE FFFF
GGGG HHHH
IIII LLLL MMMM JJJJ

and I want to print this output (considering jus the forth line also the one matching string)
AAAA BBBB CCCC DDDD
IIII LLLL MMMM JJJJ

Thanks a lot in advance.

Ciao

 

[PHV]

What about this ?

awk '/BBBB/{i=1;print}!i{next}{if(i++==4){print;i=0}}' /path/to/input

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886