how to get last day of a month 3

[dendenners]

Hi,
I want a shell script function that will take in a month number as an argument and return the last day of that month. I can assume for leap years that the incoming month is in the system's current year. This will not be difficult to do, but I can't think of a concise way to do it. Can anyone else?
Thanks

 

[dchoulette]

You could try this:

month=7
cal $month `date +%Y` | awk '/./{day=$NF};END{print day}'

It works with my version of 'cal'.

 

[dendenners]

perfect. thanks