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how to create an array of pointers
- Thread starter Maulkin
- Start date
LiquidBinary
Programmer
#include <stdio.h>
#define ELEMS 5
int main( void )
{
int i;
char* aOfs[ELEMS]={ "array",
"of",
"pointers",
"tek",
"tips"
};
char* aOfp[ELEMS];
for( i=0;i<ELEMS;i++ )
aOfp=aOfs;
for( i=0;i<ELEMS;i++ )
printf( "%s\n",aOfp );
return 0;
} Mike L.G.
mlg400@linuxmail.org
#define ELEMS 5
int main( void )
{
int i;
char* aOfs[ELEMS]={ "array",
"of",
"pointers",
"tek",
"tips"
};
char* aOfp[ELEMS];
for( i=0;i<ELEMS;i++ )
aOfp=aOfs;
for( i=0;i<ELEMS;i++ )
printf( "%s\n",aOfp );
return 0;
} Mike L.G.
mlg400@linuxmail.org
- Thread starter
- #3
thanks for the help
this will not work in my problem my string array ispopulated by a loop and looks like this if input strings are "one" "two" "three"
on the first pass the array will contain
oneNULL
on the second
oneNULLtwoNULL
on the third
oneNULLtwoNULLthreeNULL I need the pointers to point to the
O in One the T in Two and the T in Three
is this possible.
this will not work in my problem my string array ispopulated by a loop and looks like this if input strings are "one" "two" "three"
on the first pass the array will contain
oneNULL
on the second
oneNULLtwoNULL
on the third
oneNULLtwoNULLthreeNULL I need the pointers to point to the
O in One the T in Two and the T in Three
is this possible.
LiquidBinary
Programmer
Not too sure what you are getting at, but I'll give it another go...
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#define ELEMS 5
#define ELEMS_X 20
int main( void )
{
int i;
char matrix[ELEMS][ELEMS_X];
char* aOfp[ELEMS];
char* aOfs[ELEMS]={ "One",
"Two",
"Three",
"Four",
"Five"
};
for( i=0;i<ELEMS;i++ )
strcpy( matrix,aOfs );
for( i=0;i<ELEMS;i++ )
aOfp=matrix;
for( i=0;i<ELEMS;i++ )
{
printf( "%c - ",aOfp[0] );
printf( "%s\n",aOfp );
}
return 0;
}
1. The first for loop inserts the strings into a 2d array.
2.The second loop sets an array of char pointers to point to each string in matrix[][]
3.The last loop prints out the first char and the entire string via the array of pointers. Mike L.G.
mlg400@linuxmail.org
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#define ELEMS 5
#define ELEMS_X 20
int main( void )
{
int i;
char matrix[ELEMS][ELEMS_X];
char* aOfp[ELEMS];
char* aOfs[ELEMS]={ "One",
"Two",
"Three",
"Four",
"Five"
};
for( i=0;i<ELEMS;i++ )
strcpy( matrix,aOfs );
for( i=0;i<ELEMS;i++ )
aOfp=matrix;
for( i=0;i<ELEMS;i++ )
{
printf( "%c - ",aOfp[0] );
printf( "%s\n",aOfp );
}
return 0;
}
1. The first for loop inserts the strings into a 2d array.
2.The second loop sets an array of char pointers to point to each string in matrix[][]
3.The last loop prints out the first char and the entire string via the array of pointers. Mike L.G.
mlg400@linuxmail.org
My problem is similar to this one.
I too need to create array of pointers.
char* aOfs[]={ "One",
"Two",
"Three",
"Four",
"Five"
};
In the above declaration, I don't have ELEMS as it was. So i don't know the total strings in the array. I need to point each one of those strings and display the two strings on the LCD two at the time.
thanks in advance
HKC
I too need to create array of pointers.
char* aOfs[]={ "One",
"Two",
"Three",
"Four",
"Five"
};
In the above declaration, I don't have ELEMS as it was. So i don't know the total strings in the array. I need to point each one of those strings and display the two strings on the LCD two at the time.
thanks in advance
HKC
To be able to do what you want to do you will need an index for your array,you might use "#define ELEMS 5" like in the previous example or something like "const int ELEMS = 5".But without an index you wont be able to achieve it.
let say that you have one,now to print the strings two at the time,you could use this:
int i = 0;
while( i < ELEMS )
{
if( i < ELEMS - 1 )
{
printf("%s",aOfs[i++]);
printf(" %s\n",aOfs[i++]);
}
else
{
printf("%s",aOfs[i++]);
}
}
let say that you have one,now to print the strings two at the time,you could use this:
int i = 0;
while( i < ELEMS )
{
if( i < ELEMS - 1 )
{
printf("%s",aOfs[i++]);
printf(" %s\n",aOfs[i++]);
}
else
{
printf("%s",aOfs[i++]);
}
}
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