How: member-x in a list is also member-y

[Shizuka7]

Hello! I am new here in the forum, and I also a noob in programming Prolog, so if you could help me, I would very much appreciate it
How can I write in Prolog the following: that a member of a list, let's say, member1 is also member2 or member3, but not both of them?

Thank you very much!
Shizuka

 

[joel76]

That's not very clear !
What do you mean by member1 is also member2 ?
Can you give an example with a list !

 

[Shizuka7]

Thank you for answering.
I am doing a "game" in which I have six suspects with different traits:

suspect(Name, Age, Weapon, Shape, Object, Shoes)
The goal is to implement a series of clues so that the program says which the different traits of all the six suspects. For example:

suspect(Valdemort,150,winchester,'in good shape',book,'high heels').

I am having difficulties with this clue:

or(suspect1, suspect2, suspect3, listOfSuspects)

This clue is supposed to say that the suspect1 has the same traits as suspect2 OR as suspect3 but not both. Example: To indicate that the suspect who is 50 years old has a ring or a mac, but not both:

or(suspect(_, 50, _, _, _, _),
suspect(_, _, _, _, ring, _),
suspect(_, _, _, _, mac, _), listOfSuspects).

Thanks for helping.

 

[joel76]

Is is possible that sameas(S1, S2) and sameas(S1, S3) implies sameas(S2,S3) ?