How do I read the return value from a function that returns a pointer?

[SpeedBWild]

I have a function that is designed as

const char* NameOfFunction(void);

How do I get the result from that function call? I can not change the function call.

Here is what I have tried.

char *retValue;

retValue=NameOfFunction;

this does not seem to work. Any help would be appreciated.

 

[Prattaratt]

Try:

retValue = NameOfFunction();

Leaving off the Parentheses will give the compiler a coniption fit.

90% of all questions can be answer by the Help file! Try it and be amazed.

 

[BuilderSpec]

It "may" also be used like this

char MyVar[20];

memset ( MyVar , 0 , 20 );
strcpy ( MyVar , NameOfFunction() );

Then you can use MyVar ( a local variable ) to access the function result.

Hope this helps!

Regards

BuilderSpec