HuntsvilleRob
Programmer
Hello. I have posted this question before but I still don't have an answer. Your help would be MOST appreciated!
What I want to do is really very simple. I wish to launch an OpenDialog from my app and I wish to set the position to be in the center of the parent window. However, there is no Top or Left property for the OpenDialog. There is not even a Position property. The Windows OS is deciding where the OpenDialog will be positioned and I don't know how to control this. How do I set the Left, Top, and/or Position of the OpenDialog? Thanks so much.
-Rob
What I want to do is really very simple. I wish to launch an OpenDialog from my app and I wish to set the position to be in the center of the parent window. However, there is no Top or Left property for the OpenDialog. There is not even a Position property. The Windows OS is deciding where the OpenDialog will be positioned and I don't know how to control this. How do I set the Left, Top, and/or Position of the OpenDialog? Thanks so much.
-Rob