Hi I have a list of file names

[kaushik222]

Hi
I have a list of file names of flat feeds in a text file in the following format
filenames.txt
-----------------
file1.feed
file2.feed
file3.feed
file4.feed .........approx 25 filenames

these files exists in a perticular /SRCDIR...

"|" is the delimiter for each column in each one of these files

I need to search for the number of columns and rows in every feedfile.

But I do it manually by giving the columns less than some number and try to know it this way
awk 'BEGIN {FS=&quot;|&quot;} NF < 20' < FeedFileName | wc -l

Is there way, where it takes one filename at a time from filenames.txt and get the number of columns and rows, puts the output into one single file output file.

 

[Salem]

Well you could make AWK see one file at a time using this

for i in `cat filenames.txt`; do
  echo $i
  awk 'BEGIN {FS=&quot;|&quot;} NF < 20' < $i | wc -l
done

This is a sh/bash/ksh loop, the syntax in csh is a little different.


--

http://www.catb.org/~esr/faqs/smart-questions.html

 

[PHV]

Try something like this:

awk -F'|' '{nf=0;nr=0;feed="/path/to/"$1
while((getline <feed)>0){nf=NF;++nr}
close(feed);printf &quot;%s\t%d\t%d\n&quot;,feed,nf,nr
}' filenames.txt

Hope This Help
PH.

 

[kaushik222]

Hi PHV
thanks for the script, but it is not working
Anything with GETLINE is giving the following error

awk: syntax error near line 1
awk: illegal statement near line 1