Hi
I am not sure if I'm right here but although this is a php page, I have a html problem.
I want a DIV container which streches 100% of the visible screen bur it just doesn't seem to work ther is always a gap on the right hand side.
Here is the code!
<body>
<?php
include ("inc/header.html" ?>
<!--<DIV id="header" class="header" style="position:absolute; left:0px; top:0px; rightx; width:100%; height:100px; z-index:1" ><IMG src="/images/header1.jpg" width="600px" height="100" align="left"></DIV>-->
<?php
include ("inc/footer.html" ?>
<!-- <TABLE width="100%" align="center"><tr><td align="center">powered by:</td></tr><tr>
<td align="center"><IMG src="logo.jpg" width="100" height="40" border="0" /></td>
</tr></TABLE>-->
</body>
Any Hints would be appreciated
I am not sure if I'm right here but although this is a php page, I have a html problem.
I want a DIV container which streches 100% of the visible screen bur it just doesn't seem to work ther is always a gap on the right hand side.
Here is the code!
<body>
<?php
include ("inc/header.html" ?>
<!--<DIV id="header" class="header" style="position:absolute; left:0px; top:0px; rightx; width:100%; height:100px; z-index:1" ><IMG src="/images/header1.jpg" width="600px" height="100" align="left"></DIV>-->
<?php
include ("inc/footer.html" ?>
<!-- <TABLE width="100%" align="center"><tr><td align="center">powered by:</td></tr><tr>
<td align="center"><IMG src="logo.jpg" width="100" height="40" border="0" /></td>
</tr></TABLE>-->
</body>
Any Hints would be appreciated