HELP 1

[RajashreeDasari]

I am new to c language. I need to analyse a c code in which am not able to understand this lines :- nine = (u16)(in>>7);seven = (u16)(in&0x7F);
Can anybody help me understanding it.

 

[cpjust]

That is 2 different statements:

nine = (u16)(in>>7);
seven = (u16)(in&0x7F);

>> is the right shift operator. In this case it is shifting the value of in right 7 bits, casting it to a u16 (presumably a 16-bit unsigned int) and assigning the result to the nine variable.

& is the bitwise AND operator. In this case it is ANDing in with 0x7F, casting it to a u16 type and assigning it to the seven variable.