Help with sed one liner

[jouell]

Hi

How can I make sed happy with this command:

sed -i -e #"${ID_IN_PASSWORD_QUEUE}${DELIM1}${PASSWORD_IN_PASSWORD_QUEUE}"#d



I can replace the text with blanks first instead (with s###g) and then remove the blanks with:

sed -i -e /'^ *$'/d $1


But I keep getting error when I try to do it in one step.

sed: option requires an argument -- e

I know my quotes must be wrong....

Can anyone lend a pair of eyes?

 

[feherke]

Hi

The slash delimite could be replaced with something else only in the [tt]s///[/tt] command, not in the pattern.

And is not clear where is the file name in your first command.

Eventually you can show some possible values of your variables too.

Feherke.

http://rootshell.be/~feherke/

 

[SamBones]

The [tt]#[/tt] is a comment character. Your command line basically ends with that first [tt]#[/tt].

I'm not really clear on the pattern you're trying to match on. It would help if you can clarify that.

Try this...

sed -i -e "#${ID_IN_PASSWORD_QUEUE}${DELIM1}${PASSWORD_IN_PASSWORD_QUEUE}#d"

Put your edit commands in either single or double quotes and you should be ok.

Hope this helps.

 

[jouell]

Thanks for the respsonses.

I don't know what the pattern is. It is a user defined field. An example , however would be:

3+12346+/bin/cat /etc/passwd | sort

But it would be passed in via the variables above, where DELIM1 is the "+" sign.


hence I know I will be dealing with "/" characters much more than (if at all) the "#".

Does this make sense?

Thanks for all the input!

 

[jouell]

Well I gave up on my crazy method.
I think it was needlessly complex.

Instead, I am removing a line based on the unique ID number it starts with:

sed -i -e /"^$ID_IN_PASSWORD_QUEUE"/d $1

and this much more stable for my script.

I guess sometimes simple is better!

Thanks for all the help!

-John