Help with array "cleaning"

[ronnie98]

Hi all,
i have this array

Array ( [0] => . [1] => .. [2] => serverstats.php [3] => phpstats.php [4] => phpstats.php~ [5] => serverstats.php~ )

It retrieves the values by scanning a directory where there are only two files

serverstats.php and phpstats.php

For some strange(for me) reason it also loads

serverstats.php~ and phpstats.php~

into the array.
My goal is to clean the array above from "~" and ".php"
and put only the filenames into variables like these:

$first_file = "serverstats";
$second_file = "phpstats";

Thanks in advance for helping.

 

[DRJ478]

Have you considered using glob() to just retrieve the files by specific pattern?

http://www.php.net/glob/

That way you could just load all .php files and no celaning would be necessary.

 

[JRSofty]

I did something like this but for includes not for storing into an array.

Here is the code that can be modified for it

	if($handle = opendir("{$CONFIG['root']}/sources/mods")){ // This checks that the directory is opened if not it doesn't fire
		while(false !== ($filename = readdir($handle))){ // This loops through all files in the directory
			if(preg_match('/m_([^\.php]+)\.php/',$filename)){ // this looks for files that start with m_ and end with .php. 
				include("mods/{$filename}");
			}
		}
		closedir($handle);
	}

It uses a Regular Expression to ensure that only the files I want are accessible.

JRSofty

http://jrsofty.stinkbugonline.com

 

[ronnie98]

Thank you JRSofty,
your code helped me to find the solution.
ATB,ronnie

 

[DRJ478]

Again, why write your own function if PHP has a native function that does exactly the same?

foreach (glob("*.php") as $filename) {
   echo "$filename size " . filesize($filename) . "\n";
}

How could it be more simple?