Help on "ls -l $* ¦ awk '{ print $9}'+ grep $9 pattern>> result"

[narenpalepu]

Hi All

I am a starting with awk I like to grep for a pattern from all the files in directory and save the result to a file with file name. please help me out.
My seudo script
"ls -l $* | awk '{ print $9}'+ grep $9 pattern >> result"

Thanks

Naren

 

[walnz]

You can use AWK to do the regular expression match without needing to subsequently grep - e.g. ...

ls -l * | awk '/regexp/ print $9'
or grepping a specific field ..
ls -l * | awk '$n =~ /regexp/ print $9'

sorry it's been a while but I think syntax is correct