Help: find command need to display only name of the file 2

[annanathan]

Hi all,

I need help to understand how to use the find command to get the name of the file only.

find d:/something/ -name "*.txt" -exec another_script.sh {} \ ;

I need to pass only the name of the file found in the 'another_script.sh'. (extenstion excluded also)

Thank you in advance...
Any help is appreciated.

 

[olded]

Hi:

I'm not exactly certain what you want to do. The find command you've posted says to search the d:/something directory for every object with a ".txt" extension and call script another_script.sh.

I'm assuming (?) you want each file going to this script to have only the name. If that's the case, use the basename command. Place basename $1

as the first line in another_script.sh?

Regards,


Ed

 

[annanathan]

HI Ed,
The $1 gives me the full path with the name of the file found: eg d:/something/name_of_file.txt

I just need 'name_of_file' to show... eliminating the path and the extension.

Thank you in advance.

Jey

 

[olded]

Jey:

How about this as the first line in another_script.sh:

file=`basename $1|cut -f1 -d "."`

cut out just the first field where the delimiter is "."?

Regards,


Ed

 

[annanathan]

Thank you very much...
This is exactly what I was looking for...

Regards,
Jeya

 

[dchoulette]

The basename command can remove the extension if you know it:

file=`basename  $1  .txt`

 

[olded]

dchoulette:

I know this thread is old, but I'm behind on my reading. I did not know you could do this with basename. Guess I should be reading the man pages closer.

Thanks!

Ed