greping in a date range

[jalge2]

Hi all, I'm trying to grep for a certain battery number between files. The files are named batlog.log.date

date = (yyyymmdd) ex. 20030708

I'm not exactly sure how to grep for a certain number in between a said number of files. Here is what I have so far. print "\tPlease enter the battery number that you wish to search for (y/n)\c"
+6 read ans
+7
+8 print "\tPlease enter the first date you wish to search for (yyyymmdd)\c"
+9 read date1
+10
+11 print "\tPlease enter the second date you wish to search for (yyyymmdd)\c"
+12 read date2
+13
+14 if [[ $ans != 0 ]]
+15
+16 then

after this I seem to get a little stumped on how to attack this monster. Can someone help?

 

[Salem]

Assuming that the files have timestamps which reflect the date in the filename, like this

-rw-rw-r--    1 spc      spc             0 Jul  3 00:00 batlog.log.20030703

Then you could try this

touch -t ${date1}0000 oldest_file
touch -t ${date2}0000 newest_file

# find files between those two dates and search in them
find . -name "batlog.log.*" -newer oldest_file ! -newer newest_file -exec grep $ans {} \;

The find command has a large number of possibilities for finding files based on all sorts of criteria.

 

[pmurray99]

#!/usr/bin/ksh

Fdate=20030702
Ldate=20030704

ans=x

ls -1 bat.log* | while read -- File
do
[[ ${File##*.} -ge $Fdate && ${File##*.} -le $Ldate ]] &&
grep $ans $File /dev/null
done

 

[Ygor]

Not tested, but worth a try...

filelist=$(ls -1 batlog.log.*|awk /$date1/,/$date2/)
grep $ans $filelist

 

[jalge2]

Salem,

What if the time stamps are all at different times? They are a couple minutes different on each instance?

 

[Salem]

So long as the YYYYMMDD part of the filename is consistent with the timestamps, the HHMMSS of the timestamp wont matter.

If you want date1 to date2 inclusive, you might want

touch -t ${date2}2359.59 newest_file