grep question

[stephenk1973]

I have a long list of directory/files which contain a phrase. I obtain this using....

fgrep -l phrase * > file

This is good, but it is a parameter after the phrase on the same line which i really require. Can i modify this so that the line is printed as well as the file name and location.

Thanks

Stephen

 

[Chacalinc]

could you post an example pls? with the source and what you need..

thanks

 

[stephenk1973]

There are number of report files in a number of directories, some of which contain a phrase, the phrase declares a numeric format.....

.declare phrase 99999999

The phrase is about to 'roll over' and require another digit. I would like to list the file name,location and the line for each occurence of the phrase so that i will be able read which report files are effected and therefore adjust them.

Thanks

Stephen

 

[kojack96]

Maybe something like this..

fgrep -l phrase | awk -F {$3} | grep 9999999 * > file

basically grab the number via awk then grep for 9999999

I am not at work so I can't comfirm the syntax but should lead you in a direction not sure if it will be the direction you are looking for but I tried.