Grep or Cut 1

[xyz786]

Hello,
How can i get the output value 5424 from a a file containing the line 339 (5424 megabytes) using grep or cut or anything.

 

[mrn]

cat filename.txt | grep "^339 (" | cut -c 6-9

Mike

"A foolproof method for sculpting an elephant: first, get a huge block of marble, then you chip away everything that doesn't look like an elephant."

http://www.airport-parking-site.co.uk/

 

[mrregan]

grep "339 (" yourfilename | cut -c6-9

 

[Annihilannic]

Personally I would use something like:

[tt]grep 339 yourfilename | cut -d '(' -f 2 | cut -d ' ' -f 1[/tt]

That way it would also work if it was 5424 megabytes, 54242424 megabytes or 5 megabytes.

Annihilannic.

 

[xyz786]

Thanks Guys for your quick responses.

 

[mrn]

I've got to get out of the habit of using cat.......

Mike

"A foolproof method for sculpting an elephant: first, get a huge block of marble, then you chip away everything that doesn't look like an elephant."

http://www.airport-parking-site.co.uk/

 

[SamBones]

But I like cats!

cat < x.dat | cat | grep "^339 (" | cat | cut -c 6-9 | cat | cat | cat | cat

 

[feherke]

Hi

using grep or cut or anything.

Could that anything be [tt]sed[/tt] ?

sed -n '/339/s/.*(\([[:digit:]]\+\) .*/\1/p' /input/file

Note that the above was tested only with GNU [tt]sed[/tt].

Feherke.

http://rootshell.be/~feherke/