Grep on ; and also print the line and 3 above it 2

[beaster]

I hope I have not been too much today, my script keeps changing.

I have a file which has a print out like such below:

DATE TIME TRTYPE PRCA USER IO
2002-05-16 080258 C AMTP-0

ALLIP;

The file is named cmd_out. I need to grep on the file for ; (semicolon) then send that line and the three above it to another file > beaster1

Any suggestions?

Thanks,
Beaster

 

[CaKiwi]

You could use the following awk script.

/;/{print a1;print a2;print a3;print}
   {a1=a2;a2=a3;a3=$0}

Hope this helps. CaKiwi

 

[beaster]

CaKiwi,
Your responses have always been the ones that have solved my problems, but today I feel like an idiot for asking, but what would be the complete awk format for this?

Again, Thanks for your help!

Beaster

 

[CaKiwi]

You could put the script into a file, a.awk say, and enter

awk -f a.awk your-file > out-file

Hope this helps.
CaKiwi

 

[beaster]

That was it! Thanks CaKiwi, as always you have been a great help! Works perfect!

Beaster

 

[dickiebird]

Then give him a star !
;-) Dickie Bird
db@dickiebird.freeserve.co.uk