Grep for every occurance 1

[abovebrd]

Sorry for posting this, I am sure its been answered many times, I search this forum later on

Question:

I need to search for every occurance of a specific string within every file conatined with a directory and every subdirectory.

String=192.168.1.23

I would like to output to a file listing

Thanks in advance


-Danny

 

[abovebrd]

This is what I came up with,

find ./ -exec grep -l 192.168.1.23 {} \; > /tmp/file.tmp


-Danny

 

[jzzhang71]

This command will do the work:

find dir -exec grep -l 192.168.1.23 {} \;

where dir is the top directory you want to search from.

Good luck

 

[ElgisRamon]

Even faster:
[tt]
find /initial/directory -type f -print0 | xargs -0 grep -l '192\.168\.1\.23'
[/tt]

[tt]find[/tt] will only generate file (not directory) names and separate each name with a null then spaces won't in filenames won't affect, [tt]xargs[/tt] will take the null separated names and will run [tt]grep[/tt] the minimum needed times to process all files, givin the maximum supported command line. [tt]grep[/tt] will only show the file names (because -l) and remember the dot is special to grep then you must to escape it with a \.
I hope it works...
Unix was made by and for smart people.