Grab a line under particular word... 1

[h3nd]

Hi guys

This should be simple question but I can't get it work,
I wanna grab the lines content between this gap [ERROR IN and INSTRUMENT ... ]from a particular file :

Here's the part of the content file :

...
ERRORS IN:
------------------------------------
ABCD
AB

INSTRUMENT LOAD TOTALS PER FILE ARE:
------------------------------------
...

so, the output should be :
ABCD
AB

Thanks guys

 

[feherke]

Hi

Just a strange [tt]sed[/tt] solution. When find the "ERRORS IN", skip the next line, then output the lines until finds "INSTRUMENT".

sed -n '/^ERRORS IN/{n;n;:l;/^INSTRUMENT/b;p;n;bl}' /input/file

Tested with GNU [tt]sed[/tt]. Probably not work with Unix [tt]sed[/tt]s.

And its [tt]awk[/tt] equivalent, just as ugly as the [tt]sed[/tt] one.

awk '/ERRORS IN/{getline;getline;while($0!~/^INSTRUMENT/){print;getline}}' /input/file

Feherke.

http://rootshell.be/~feherke/

 

[h3nd]

Thx feherke,

but I couldnt understand that sed.

What about in awk ?

 

[feherke]

Hi

Both are doing exactly the same thing. The only difference is that [tt]sed[/tt] has no loop command, so the b ( branch ) command and a label is used.

Feherke.

http://rootshell.be/~feherke/