Tek-Tips is the largest IT community on the Internet today!

Members share and learn making Tek-Tips Forums the best source of peer-reviewed technical information on the Internet!

  • Congratulations SkipVought on being selected by the Tek-Tips community for having the most helpful posts in the forums last week. Way to Go!

getimagesize()

Status
Not open for further replies.

dagger2002

Programmer
Nov 23, 2004
172
0
0
US
Hey all I have a hopefully quick question.

I have a site that I am building. I have a right bar that is pulling from a mysql db, version 4, and php, version 4.

I am using the getimagesize() command on a path from the db. But I am getting the following error

Code:
Fatal error: Only variables can be passed by reference in /home/globalai/public_html/dev/current/includes/right.php on line 82

here is line 82

Code:
$path = $website . substr($row2[pic_path], 27, 100);
$size = getimagesize($path, 3);

$website is just the url to the public directory.

Any Ideas?

Thanks All
 
the problem is that you are using the getImageSize function incorrectly.

the php manual gives a description of the function parameters as follows:

array getimagesize ( string $filename [, array &$imageinfo] )
this means that if you want the imageinformation you must pass a variable as the second argument. the integer "3" cannot be used as a variable. If you do not need the extended information, just pass the filename.
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor

Back
Top