get lines with an if clause

[ozi403]

name: ata
group: atagroup;
save set: /ger
/germe
storage nodes: ata2
cl OS type: yyy

name: ozan
group: ;
save set: /etc
storage nodes: ozi
cl OS type: xxx

I try to get lines between "save set:" and "storage nodes:"
if "group:" value is ";" . Then I wrote this:

awk '$1=="group:"{if($2~/;/)}{/save set:/,/storage nodes:/}'

but it prints every lines without if clause.

Thanks for helps.

 

[feherke]

Hi

If I understand correctly...

awk '$1=="group:"{v=$2!=";"}/save set:/,/storage nodes:/{if(v)print}' /input/file

If not, please rephrase the requirements.

Tested with [tt]gawk[/tt].

Feherke.

http://rootshell.be/~feherke/