Function serach coded correctly, but outputs wrong data!

[Goku]

alright here is my programming code.

// program 12.4.6
// author: mike morales
// objective: to take a two dimensional array,
// and then sort's it's elements in ascending order,
// and store them in a one dimensional array
#include <iostream>
#include<string>
using namespace std;
/*void SelectionSort(int array[],int g, int value1, int value2);*/

int Search( const int F[], int p, int Key){
for(int i=0;i<p;++i){
if(F==Key){

return i;

}
}
return p;
}
int main(){
int A[4][5] ={{16,22,99,4,18},{-258,4,101,5,98},{105,6,15,2,45},{33,88,72,16,3}}, B[100];
// no we are going to convert
int n;
cout <<&quot; number of elements?&quot; << endl;
cin >> n;


for (int r=0;r<4;++r){
for(int c=0;c<5;++c){
B[20]= A[r][c];
B[n]=B[20];
cout << B[n] << endl;
}


}
int Key;
cout << &quot; enter search value &quot; << endl;
cin >> Key;

int q = Search(B,n,22);
cout << q << endl;

return 0;
}

supposedly, the function search should return the matching subscript of that elements value. per se... i pick 22, it should return the address for that element which is 1...but i keep on getting a twenty!

is something wrong with my if statements or do i need to declare a new variable, instead of &quot;n&quot; in my search function?

plz help!

 

[palbano]

Well in your code the variable 'F' is a pointer, so this comparison:

if(F==Key){


will likely never be true and your code will return 'p'

Good luck
-pete

 

[aphrodita]

That is from your code:

for (int r=0;r<4;++r){
for(int c=0;c<5;++c){
B[20]= A[r][c];
B[n]=B[20];
cout << B[n] << endl;
}


You are not storing numbers in B array.you can use this code in the body of the loop.
{
static int q=0;
B[q]=A[r][c];
cout<<B[q]<<endl;
q++;
}

P.S. To grab size of the array use: sizeof(array_name)/sizeof(classofVariableused); Best Regards,

aphrodita@mail.krovatka.ru {uiuc rules}

http://www.hellforge.org