freeing char memory

[SteveBrett]

Hi

if I have the following code:

char szContentLength[50];
memset(szContentLength, 0, 50);

do i need to delete szContentLength to free up the memory or will it be free when it goes out of scope ?

Many thanks

Steve

 

[Diancecht]

When an array is declared as above, memory is allocated for the elements of the array when the program starts, and this memory remains allocated during the lifetime of the program. This is known as static array allocation.

from

http://www.hermetic.ch/cfunlib/arrays/arrays.htm

Cheers,
Dian

 

[SteveBrett]

the article seems to relate to C and i'm using c++ ...

would static array alloaction need to be deleted then ? or will it be freed when it goes out of scope - as a general rule i delete memory that is new'd.

thanks

Steve

 

[Diancecht]

AFAIK,it works the same way for C and C++:

http://www.chips.navy.mil/archives/99_apr/c++arrays.htm

The memory will be reserved at the beginning and freed at the end.


Cheers,
Dian

 

[uolj]

Of course, even though static arrays work the same in C and C++ in this case (there is a difference in that C++ requires a compile-time constant size), C++ has extra tools for the job.

In C++, you would generally use the C++ string class or a vector, deque, or std::tr1::array. ;-)

 

[Salem]

> do i need to delete szContentLength to free up the memory or will it be free when it goes out of scope ?
If you call [tt]new[/tt], then call [tt]delete[/tt] at some point later on, when you're done.

And if you do a [tt]new[size][/tt] then do a [tt]delete[][/tt] and not a [tt]delete[/tt]

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