Fortran coding issues

[Newbie911]

[pre][/pre]

Hi,

In the following piece of code, I want to vary lambda and Gamma but in such a way that the product of lambda and gamma remains 2, ie Lambda*gamma=2

I am unsure how to do this,

The program also reads in an initial value of gamma and lambda from an input file which I can specify.

do ll = 1, 7
! gam=1.0e-3*facg
gam = 1/1024.*2.0**(ll - 1)
do mm = 1, 7
! lambda=1.0e+3*facl
lambda = 64*2.0**(mm - 1)

 

[salgerman]

Well...you cannot have 2 do-loops and one nested inside the other...this way, you will be generated all 7 values of the inner variable (lambda) for every 1 value of the outer one (gam).

You said it yourself, lambda*gamma=2...that's one equation, two unknowns...as soon as 1 variables is defined, the other one is determinable...given gamma =.125 ==> lambda = 2.0/gamma = 8.0

 

[Newbie911]

Thank you for your reply salgerman,

So how should I change the code to vary them both automatically but keep the product 2?

 

[salgerman]

Get rid of the inner loop, just use the outer one where you define gamma, then, simply define lambda as showed above: lambda = 2.0/gamma